ifft
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constexpr std::vector<Complex> ifft(const std::vector<Complex> &X) noexcept
Calculates the inverse fast Fourier transform [1] of a complex sequence.
Parameters
Returns
The fast inverse Fourier transform performs the discrete Fourier transform, defined as follows:
\[\DeclareMathOperator\H{H}
X_k = \frac{1}{n}\sum_{m = 0}^{n - 1}x_m e^{2\pi km/n} \quad k = 0, \ldots, n-1,\]
The transform is made to perform in \(O(n\log(n))\) time using the Cooley-Tukey algorithm [2].
Example
std::vector<Complex> X = {1 + 2_j, 2 + 3_j, 3, 4, 5};
std::vector<Complex> Y = fft(X);
for(int i = 0; i < Y.size(); i++){
std::cout << Y[i] << "\n";
}
Output:
15 + 5j
0.35317 + 6.36801j
-0.736644 + 0.385248j
-4.26336 - 1.23935j
-5.35317 - 0.513904j
References